0=-4(x^2-49)

Solution for 0=-4(x^2-49) equation:

0=-4(x^2-49)

We move all terms to the left:

0-(-4(x^2-49))=0

We add all the numbers together, and all the variables

-(-4(x^2-49))=0


We calculate terms in parentheses: -(-4(x^2-49)), so:

-4(x^2-49)

We multiply parentheses

-4x^2+196

Back to the equation:

-(-4x^2+196)


We get rid of parentheses

4x^2-196=0

a = 4; b = 0; c = -196;
Δ = b2-4ac
Δ = 02-4·4·(-196)
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3136}=56$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-56}{2*4}=\frac{-56}{8}
=-7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+56}{2*4}=\frac{56}{8}
=7
$